question_answer

The centre of a wheel rolling on a plane surface, moves with a speed \[{{V}_{0}}\]. A particle on their rim of the wheel at the same level as that centre will be moving at speed:

A)  zero                

B)  \[{{V}_{0}}\]

C)  \[\sqrt{2{{V}_{0}}}\]                      

D)  \[2{{V}_{0}}\]

Correct Answer: C

Solution :

Here, from the figure the resultant speed of P, \[{{V}_{P}}=\sqrt{V_{0}^{2}+V_{0}^{2}}=\sqrt{2{{V}_{0}}}\]