A) zero
B) \[13\,N\]
C) \[3.3\,N\]
D) \[19.6\,N\]
Correct Answer: B
Solution :
From the figure, Free body diagrams of A, B and C \[a=\frac{40-20}{6}=\frac{10}{3}\] Also, \[20-T=2a\] \[\Rightarrow \] \[T=\frac{40}{3}=13.33\,\cong 13N\]You need to login to perform this action.
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