A conductor in the form of the right triangle ABC with \[AB=3cm\]and \[BC=4cm\]carries a current of 10A. There is a uniform magnetic field of 5T perpendicular to the plane of the conductor. The force on the conductor AC will be:
A) \[1.5\,N\]
B) \[2.0\,N\]
C) \[2.5\,N\]
D) \[3.5\,N\]
Correct Answer:
C
Solution :
Force on the conductor ABC = Force on the conductor AC \[=5\times 10\times (5\times {{10}^{-2}})=2.5N\]