A) \[\frac{qbB}{m}\]
B) \[\frac{q(b-a)B}{m}\]
C) \[\frac{qa\,B}{m}\]
D) \[\frac{q\,(b+a)}{2m}\]
Correct Answer: B
Solution :
As \[\frac{m{{V}^{2}}}{r}=qVB\] or \[V=\frac{qB}{m}\,(r)\] \[\therefore \] \[{{V}_{\min }}=\frac{qB}{m}({{r}_{\min }})=\frac{qB}{m}(b-a)\] Note that r should be \[(b-a)\] to go just outside of field rigid.You need to login to perform this action.
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