A) \[\frac{-q}{1+\sqrt{2}}\]
B) \[\frac{2q}{2+\sqrt{2}}\]
C) \[-2q\]
D) \[+q\]
Correct Answer: B
Solution :
As net potential energy = 0 \[\Rightarrow \] \[K=\frac{Qq}{a}+\frac{K{{q}^{2}}}{a}+\frac{KQq}{\sqrt{2a}}=0\] \[\Rightarrow \] \[Q+q+\frac{Q}{\sqrt{2}}=0\] \[\therefore \] \[Q=\frac{2q}{(2+\sqrt{2})}\]You need to login to perform this action.
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