A) \[PbC{{l}_{4}}\]
B) Cone. \[HCl\]
C) \[CrC{{l}_{3}}\]
D) Cone. \[{{H}_{2}}S{{O}_{4}}\]
Correct Answer: B
Solution :
Cone. \[HCl\] will convert permanganate ion \[\left( MnO_{4}^{-} \right)\] to manganous \[\left( M{{n}^{2+}} \right)\] ion. \[2KMn{{O}_{4}}+16HCl\xrightarrow{{}}2KCl+MnC{{l}_{2}}+8{{H}_{2}}O+5C{{l}_{2}}\]You need to login to perform this action.
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