A) \[\frac{4q}{\sqrt{3\pi }{{\varepsilon }_{0}}b}\]
B) \[\frac{\sqrt{3}q}{\pi {{\varepsilon }_{0}}b}\]
C) \[\frac{2q}{\pi {{\varepsilon }_{0}}b}\]
D) zero
Correct Answer: A
Solution :
\[\therefore \] \[Vneta{{t}_{0}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{\left( \frac{b/\sqrt{3}}{2} \right)}\times 8=\frac{4q}{\sqrt{3}\pi {{\varepsilon }_{0}}b}\] (As distance of charge from the corners is \[\frac{b\sqrt{3}}{2}\])You need to login to perform this action.
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