A) \[\frac{\sqrt{3}}{4}\,\frac{{{l}^{2}}}{R}\]
B) \[\frac{4}{\sqrt{3}}\,\frac{{{l}^{2}}}{R}\]
C) \[\frac{\sqrt{3}}{4}\,\frac{R}{{{l}^{2}}}\]
D) \[\frac{4}{\sqrt{3}}\,\frac{R}{{{l}^{2}}}\]
Correct Answer: A
Solution :
As \[\phi =\frac{\sqrt{3}}{4}{{l}^{2}}B\] Therefore, induced emf \[\varepsilon =\left| \frac{d\phi }{dt} \right|=\frac{\sqrt{3}}{4}{{l}^{2}}\frac{dB}{dt}\] \[i\Rightarrow \frac{\varepsilon }{R}=\frac{\sqrt{3}{{l}^{2}}}{4R}\] (Here i = induced current).You need to login to perform this action.
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