A) \[40m\]
B) \[80m\]
C) \[80\sqrt{2m}\]
D) \[\frac{80}{\sqrt{2}}m\]
Correct Answer: C
Solution :
[c] Range \[=20\times 4=80m\] Y (vertical distance) \[=\frac{1}{2}\times 10\times {{(4)}^{2}}=80m\]Displacement \[=\sqrt{{{R}^{2}}+{{Y}^{2}}}=\sqrt{{{(80)}^{2}}+{{(80)}^{2}}}\Rightarrow 80\sqrt{2m}\]You need to login to perform this action.
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