A) 4
B) 2
C) 3
D) 44
Correct Answer: D
Solution :
[d] Frequency \[({{f}_{1}})=\frac{v}{\lambda }=\frac{396}{{}^{100}/{}_{100}}=396Hz\] \[{{f}_{2}}=\frac{396}{90\times {{10}^{-2}}}=440Hz\] No. of beats =\[{{f}_{2}}-{{f}_{1}}\] \[=440-396=44Hz\]You need to login to perform this action.
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