A) \[1\times {{10}^{-4}}\,mol{{L}^{-1}}{{S}^{-1}}\]
B) \[3\times {{10}^{-4}}\,mol{{L}^{-1}}{{S}^{-1}}\]
C) \[4\times {{10}^{-4}}\,mol{{L}^{-1}}{{S}^{-1}}\]
D) \[6\times {{10}^{-4}}\,mol{{L}^{-1}}{{S}^{-1}}\]
Correct Answer: B
Solution :
[b] \[3\times {{10}^{-4}}\,mol\,\,{{L}^{-1}}{{s}^{-1}}\] \[{{N}_{2}}+3{{H}_{2}}\to 2N{{H}_{3}}\] \[Rate\,=-\frac{1}{3}\frac{\Delta [{{H}_{2}}]}{\Delta t}\] \[=+\frac{1}{2}\frac{\Delta \,[N{{H}_{3}}]}{\Delta t}\] \[Or\,-\frac{\Delta \,[{{H}_{2}}]}{\Delta t}=+\frac{3}{2}\frac{\Delta [N{{H}_{3}}]}{\Delta }\] \[=\frac{3}{2}\times 2\times {{10}^{-4}}\] \[3\times {{10}^{-4}}\,mol{{L}^{-1}}{{s}^{-1}}\]You need to login to perform this action.
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