A) 0.365
B) 36.5
C) 100
D) 150
Correct Answer: C
Solution :
[c] 100 200 mL of the sol. require = 0.73 g HC1 \[=\frac{0.73}{36.5}mol\] \[=0.02mol\] \[=20\,m\,mol\] \[\therefore \,1000mL\,(1L)\,of\,the\,sol.\,will\,require\,\] \[=\frac{20}{200}\times 1000=100m\,\,mol\]You need to login to perform this action.
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