A) 10h/Ti
B) 2.5h/7i
C) 25h/7i
D) 1.0h/Ti
Correct Answer: B
Solution :
[b] \[2.5h/\pi \] Angular momentum \[\frac{nh}{2\pi }\] In 5th orbit \[=\frac{5h}{2\pi }=2.5\frac{h}{\pi }\]You need to login to perform this action.
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