A) 3
B) 6
C) 9
D) Zero
Correct Answer: D
Solution :
[c] Potential energy \[=\frac{K}{2}\] \[mg{{h}_{1}}=\frac{1}{2}\times 490\] \[2\times 9.8\times {{h}_{1}}=\frac{490}{2}\] \[{{h}_{1}}=12.5m\]You need to login to perform this action.
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