A) 8 : 1
B) 4 : 1
C) 2 : 1
D) 1 : 8
Correct Answer: B
Solution :
[b] When 8 small drops, each of radius r combined to form big drop \[{{V}_{2}}={{n}^{{}^{2}/{}_{3}}}\,{{V}_{1}}\] \[{{V}_{2}}={{(8)}^{{}^{2}/{}_{3}}}\,{{V}_{1}}\] \[{{V}_{2}}={{(2)}^{3\times \frac{2}{3}}}\,{{V}_{1}}\] \[\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{4}{1}\]You need to login to perform this action.
You will be redirected in
3 sec