A) 0.05
B) 0.06
C) 0.01
D) none of these
Correct Answer: B
Solution :
\[E=\frac{1}{2}\,m{{\omega }^{2}}{{A}^{2}}\] \[=\,\,E=\frac{1}{2}m\,{{(2\pi f)}^{2}}{{A}^{2}}\,\,\,\,\,\,\Rightarrow \,\,\,A=\frac{1}{2\pi \,f}\,\,\sqrt{\frac{2E}{m}}\,\] \[Putting\,\,E=K+U\,\,we\,\,obtain,\] \[A=\frac{1}{2\pi \left( \frac{24}{\pi } \right)}\,\sqrt{\frac{2\times (0.5)+0.4}{0.2}}\,\,\,\Rightarrow \,\,A=\frac{1}{2\pi f}\,\sqrt{\frac{2\,E}{m}}\,\]
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