A) 0.2 A
B) 0.4 A
C) zero
D) 0.1 A
Correct Answer: A
Solution :
Since diode in upper branch is forward biased and in lower branch is reversed biased. So current through circuit \[i=\frac{V}{R+r}\] here \[{{r}_{d}}=diode\] \[resistance\text{ }in\text{ }forward\text{ }biasing\text{ }=\text{ }0\] \[\Rightarrow \,\,i=\frac{V}{R}=\frac{2}{10}=0.2\,\,A\]You need to login to perform this action.
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