A) \[\sqrt{2gh}\]
B) \[\frac{M+m}{m}\,\sqrt{2gh}\]
C) \[\frac{m}{M+m}\,2gh\]
D) \[\frac{M+m}{M}\,\sqrt{2gh}\]
Correct Answer: A
Solution :
Initial K.E. of block when bullet strikes to it \[=\,\,\frac{1}{2}\,(m+M){{V}^{2}}\] Due to this K.E. block will rise to a height h. \[\operatorname{Its} potential energy =\left( m + M \right)gh.\] By the law of conservation of energy \[\frac{1}{2}(m+M){{V}^{2}}=\,\,(m+M)\,gh\,\,\,\,\,\,\,\,\,\,\,\,\therefore \,\,\,V=\sqrt{2gh}\]You need to login to perform this action.
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