A) 50 Hz
B) 60 Hz
C) 80 Hz
D) 100 Hz
Correct Answer: C
Solution :
With \[dc:\,\,P=\frac{{{V}^{2}}}{R}\,\,\,\Rightarrow \,\,R=\frac{{{(10)}^{2}}}{20}\,\,=\,\,5\,\Omega \] \[With\,\,ac:\,\,P=\frac{{{V}^{2}}_{rms}R}{{{Z}^{2}}}\,\,\,\Rightarrow \,\,{{Z}^{2}}=\frac{{{(10)}^{2}}\times 5}{10}\,\,=\,\,50\,{{\Omega }^{2}}\] \[Also\,\,\,{{Z}^{2}}={{R}^{2}}+4{{\pi }^{2}}{{v}^{2}}{{L}^{2}}\] \[50={{\left( 5 \right)}^{2}}+4{{\left( 3.14 \right)}^{2}}{{v}^{2}}{{\left( 10\times 1{{0}^{-3}} \right)}^{2}}\] \[\Rightarrow \,\,v=80\,Hz\]
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