A) \[13.6\times 1.6\times {{10}^{-19}}\,J\]
B) \[3.4\times 1.6\times {{10}^{-19}}\,J\]
C) \[1.51\times 1.6\times {{10}^{-19}}\,J\]
D) 0
Correct Answer: B
Solution :
The electrostatic P.E. is zero when the electron and proton are far apart from each other. Work done in pulling electron and proton far away from each other \[W={{E}_{f}}-{{E}_{i}}=0-{{E}_{i}}\,=\,\,-\left( -\frac{13.6}{{{n}^{2}}}\,eV \right)\] \[\Rightarrow \,\,\,W=\frac{13.6}{{{(2)}^{2}}}\times 1.6\times {{10}^{-}}^{l9}J=3.4\,\,\times 1.6\times {{10}^{-}}^{19}J\]
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