A) \[\frac{1+p}{2\sqrt{p}}\]
B) \[\frac{2\sqrt{p}}{1+p}\]
C) \[\frac{p}{1+p}\]
D) \[\frac{2p}{1+p}\]
Correct Answer: B
Solution :
Visibility \[V=\frac{{{\operatorname{I}}_{max}}-{{\operatorname{I}}_{min}}}{{{\operatorname{I}}_{max}}+{{\operatorname{I}}_{min}}}\,\,=\,\,\frac{2\sqrt{{{I}_{1}}{{I}_{2}}}}{({{I}_{1}}+{{I}_{2}})}\] \[=\,\,\,\frac{2\sqrt{{{I}_{1}}/{{I}_{2}}}}{\left( \frac{{{I}_{1}}}{{{I}_{2}}}+1 \right)}\,\,=\,\,\frac{2\,\sqrt{P}}{(P+1)}\]
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