A) 1 hour
B) 1 day
C) 1 week
D) 1 month
Correct Answer: C
Solution :
Decay constant, \[\lambda \,\,=\,\,{{10}^{-}}^{6}{{s}^{-}}^{1}.\] The half-life \[{{T}_{1/2}}\] is thus given by \[{{T}_{1/2}}\,\,=\,\,\frac{0.639}{\lambda }\,\,=\frac{0.639}{{{10}^{-6}}}\,\,\,=\,\,0.639\times {{10}^{6}}s\] \[= 192.5 hr.\, 8 days =1.14 week \approx 1 week\]You need to login to perform this action.
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