A) half of the atomic weight
B) 1/5 of the atomic weight
C) the atomic weight
D) twice the atomic weight
Correct Answer: C
Solution :
\[Equivalent\,\,weight\,\,=\,\,\frac{Atomic\,\,weight}{No.\,\,of\,\,{{e}^{-}}\,lost\,\,or\,\,gained}\] \[F{{e}^{2+}}\to F{{e}^{3+}}\,+\,\,{{e}^{-}}\] \[\Rightarrow \,\,\,Equivalent weight=Atomic weight\]You need to login to perform this action.
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