2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-65

  • question_answer
    A tank is filled with water up to a height H. Water is allowed to come out of a hole P in one of the walls at a depth D below the surface of water. Express the horizontal distance x in terms of H and D                      

    A) \[x=\sqrt{D(H-D)}\] 

    B)   \[x=\sqrt{\frac{D(H-D)}{2}}\]

    C) \[x=2\,\sqrt{D(H-D)}\]   

    D) \[x=4\,\sqrt{D(H-D)}\]

    Correct Answer: C

    Solution :

    Time taken by water to reach the bottom \[t=\frac{2(H-D)}{g}\] and velocity of water coming out of hole, \[v=\sqrt{2gD}\] \[\therefore \] Horizontal distance covered \[x=\nu \times t\] \[=\,\,\sqrt{2gD}\,\,\times \,\,\sqrt{\frac{2(H-D)}{g}}\,\,=\,\,2\sqrt{D(H-D)}\]=


You need to login to perform this action.
You will be redirected in 3 sec spinner