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NEET Sample Paper NEET Sample Test Paper-65

  • question_answer
    A particle moves in a straight line with a constant acceleration. It changes its velocity from \[10 m{{s}^{-}}^{1}\,\,to\,\,20 m{{s}^{-}}^{1}\] while passing through a distance 135 m in t second. The value of t is

    A) 10                                

    B) 1.8

    C) 12                                

    D) 9

    Correct Answer: D

    Solution :

    Let u and v be the first and final velocities of particle and a and s be the constant acceleration and distance covered by it. Using \[{{\operatorname{v}}^{2}}= {{y}^{2}}+2as\] \[\Rightarrow \,\,\,\,{{\left( 20 \right)}^{2}}={{\left( 10 \right)}^{2}}+2a\,\,\times \,\,135\] \[or\,\,\,\,\,\,a=\frac{300}{2\times 135}\,\,=\,\,\frac{10}{9}\,m{{s}^{-2}}\] Now using, \[\operatorname{v} =u + at\] \[t=\frac{v-u}{a}=\frac{20-10}{(10/9)}\,\,=\,\,\frac{10\times 9}{10}\,\,=\,\,9\,s\]


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