A) \[{{m}^{3}}\]
B) \[c{{m}^{3}}\]
C) \[d{{m}^{3}}\]
D) none of these
Correct Answer: A
Solution :
\[J\text{ }P{{a}^{-1}}\]; Unit of work is Joule and unit of pressure is Pascal. Dimension of Joule i.e. work = \[F\times L= ML{{T}^{-}}^{2}\,\times \, L =\left[ M{{L}^{2}}{{T}^{-}}^{2} \right]\] \[\frac{1}{Pa}=\frac{1}{\Pr essure}\,\,=\,\,\frac{1}{F}=\frac{1\times A}{F}\,\,=\,\,\left[ ML{{T}^{-1}} \right]\] So. \[J\,P{{a}^{-}}^{1}=\left[ M{{L}^{2}}{{T}^{2}} \right]\,\,=\,\,\left[ {{L}^{2}}\times \,\,L \right]\,\,=\,\,\left[ {{L}^{3}} \right].\]
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