2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-65

  • question_answer
    A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M. If the block rises to a height h, the initial velocity of the block will be

    A) \[\sqrt{2gh}\]                 

    B) \[\frac{M+m}{m}\,\sqrt{2gh}\]

    C) \[\frac{m}{M+m}\,2gh\]                        

    D) \[\frac{M+m}{M}\,\sqrt{2gh}\]

    Correct Answer: A

    Solution :

    Initial K.E. of block when bullet strikes to it \[=\,\,\frac{1}{2}\,(m+M){{V}^{2}}\] Due to this K.E. block will rise to a height h. \[\operatorname{Its} potential energy =\left( m + M \right)gh.\] By the law of conservation of energy \[\frac{1}{2}(m+M){{V}^{2}}=\,\,(m+M)\,gh\,\,\,\,\,\,\,\,\,\,\,\,\therefore \,\,\,V=\sqrt{2gh}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner