A) 310 kPa
B) 210 kPa
C) 420 kPa
D) 265 kPa
Correct Answer: D
Solution :
Total volume of two flasks \[=1+3=4\] If \[{{P}_{1}}\] the pressure of gas \[{{N}_{2}}\] in the mixture of \[{{N}_{2}}\] and \[{{O}_{2}}\] then \[\operatorname{P}=100\,\,kPa,\,\,{{P}_{1}}=?,\,\,V=1\,\,litre,\,\,{{V}_{1}}=4\,\,litre\] applying Boyle?s law \[PV={{P}_{1}}{{V}_{1}}\] \[100 \times 1 = {{P}_{1}} \times 4; \,{{P}_{1}} = 25\] If \[{{P}_{2}}\] is the pressure of \[{{O}_{2}}\] gas in the mixture of \[{{O}_{2}}\] and \[{{N}_{2}}\] then, \[320\times 3={{P}_{2}}\ \times 4;\,\,{{P}_{2}}=240\] Hence, Total pressure \[\operatorname{P}={{P}_{1}}+{{P}_{2}} =25 + 240=265\,\,kPa\]
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