A) \[{{\alpha }^{2}}=\,\sqrt{\frac{{{K}_{a}}}{C}}\]
B) \[{{\alpha }^{2}}=\,\sqrt{\frac{{{C}_{a}}}{K}}\]
C) \[\alpha =\,\sqrt{\frac{{{K}_{a}}}{C}}\]
D) \[\alpha =\,\sqrt{\frac{{{C}_{a}}}{K}}\]
Correct Answer: C
Solution :
According to the Ostwald?s dilution formula\[{{\alpha }^{2}}=\frac{K(1-\alpha )}{C}\]. But for weak electrolytes \[\alpha \] is very small. So that \[(1-\alpha )\] can be neglected. So that\[\alpha =\sqrt{\frac{{{K}_{\alpha }}}{C}}\].You need to login to perform this action.
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