A) \[C{{H}_{3}}O\]
B) \[C{{H}_{2}}O\]
C) CHO
D) \[C{{H}_{4}}O\]
Correct Answer: A
Solution :
Element | Percentage | At.wt. | At. ratio | Simple Ratio |
C | 38.71 | 12 | \[\frac{38.71}{12}\] = 3.23 | \[\frac{3.23}{3.23}=1\] |
H | 9.67 | 1 | \[\frac{9.67}{1}\] = 9.67 | \[\frac{9.67}{3.23}\,=\,3\] |
O | \[100-(38.71\]\[+9.67)=51.62\] | 16 | \[\frac{51.32}{16}\] = 3.23 | \[\frac{3.23}{3.23}\,=\,1\] |
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