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NEET Sample Paper NEET Sample Test Paper-65

  • question_answer
    For the reaction \[{{N}_{2}}+3{{H}_{2}}\to 2N{{H}_{3}}\] If \[\frac{\Delta \left[ N{{H}_{3}} \right]}{\Delta t}\,=\,\,2\times {{10}^{-\,4}}\,mol\,{{1}^{-1}}\,{{s}^{-1}}\], the value of \[\frac{-\Delta \left[ {{H}_{2}} \right]}{\Delta t}\] would be

    A) \[1\times {{10}^{-4}}\,mol\,\,{{1}^{-1}}\,{{s}^{-1}}\]

    B) \[3\times {{10}^{-4}}\,mol\,\,{{1}^{-1}}\,{{s}^{-1}}\]

    C) \[4\times {{10}^{-4}}\,mol\,\,{{1}^{-1}}\,{{s}^{-1}}\]

    D) \[6\times {{10}^{-4}}\,mol\,\,{{1}^{-1}}\,{{s}^{-1}}\]

    Correct Answer: B

    Solution :

    \[{{N}_{2}}+3{{H}_{2}}\rightleftharpoons 2N{{H}_{3}}\] \[\frac{-\Delta \left[ {{N}_{2}} \right]}{\Delta t}\,\,=\,\,\frac{1}{3}\,\frac{\Delta \left[ {{H}_{2}} \right]}{\Delta t}\,\,=\,\frac{1}{2}\,\frac{\Delta \left[ N{{H}_{3}} \right]}{\Delta t}\] \[=3\times {{10}^{-4}}\,\,mol\,\,litr{{e}^{-1}}\,{{\sec }^{-1}}\]


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