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NEET Sample Paper NEET Sample Test Paper-65

  • question_answer
    An organic compound contains carbon hydrogen and oxygen. Its elemental analysis gave C,\[38.71\,%,\text{ }and\text{ }H,\text{ }9.67\,%\]. The empirical formula of the compound would be:

    A) \[C{{H}_{3}}O\]                      

    B) \[C{{H}_{2}}O\]

    C) CHO                

    D) \[C{{H}_{4}}O\]

    Correct Answer: A

    Solution :

    Element Percentage At.wt. At. ratio Simple Ratio
    C 38.71 12 \[\frac{38.71}{12}\] = 3.23 \[\frac{3.23}{3.23}=1\]
    H 9.67 1 \[\frac{9.67}{1}\] = 9.67 \[\frac{9.67}{3.23}\,=\,3\]
    O \[100-(38.71\]\[+9.67)=51.62\] 16 \[\frac{51.32}{16}\] = 3.23 \[\frac{3.23}{3.23}\,=\,1\]
    Thus empirical formula is \[C{{H}_{3}}O\].


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