A) (i)
B) (ii)
C) (iii)
D) Both (ii) and (iii)
Correct Answer: B
Solution :
At \[t= 0\] current through L is zero so it acts as open circuit. The given figures can be redrawn as follow. \[{{i}_{1}}= 0\] \[{{i}_{2}}= \frac{E}{R}\] \[{{i}_{3}}= \frac{E}{2R}\] \[Hence\,\,{{i}_{2}}>{{i}_{3}}>{{i}_{1}}.\]You need to login to perform this action.
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