2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-65

  • question_answer
    The energy absorbed by each molecule \[({{A}_{2}})\] of a substance is \[4.4 \times  1{{0}^{19}}J\] and bond energy per molecule is \[4.0 \times  1{{0}^{19}}J\]. The kinetic energy of the molecule per atom will be

    A) \[2.0\times {{10}^{-}}^{20}\,J\]

    B) \[2.2\times {{10}^{-}}^{19}\,J\]

    C) \[2.0\times {{10}^{-}}^{19}\,J\]                     

    D) \[4.0\times {{10}^{-}}^{20}\,J\]

    Correct Answer: A

    Solution :

    KE of molecule = energy absorbed by molecule - BE per molecule \[=\,\,\left( 4.4\times {{10}^{-1}}^{9} \right)-\left( 4.0\times {{10}^{-}}^{19} \right)\,J=\,\,0.4\times {{10}^{-19}}\,J\] KE per atom \[=\,\,\frac{0.4\times {{10}^{-19}}}{2}\,\,J=\,\,2.0\,\,\times \,\,\,{{10}^{-20}}J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner