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NEET Sample Paper NEET Sample Test Paper-66

  • question_answer
    The equation of stationary wave along a stretched string is given by \[y=5\,\sin \,\frac{\pi x}{3}\,\cos \,40\pi t\] where x and y are in centimetre and t in second. The separation between two adjacent nodes is

    A) 6 cm                            

    B) 4 cm

    C) 3 cm                            

    D) 1.5 cm

    Correct Answer: C

    Solution :

    Given \[y=5\,\sin \,\frac{\pi x}{3}\,\cos \,40\pi t\] Comparing with \[y=2a\cos \,\frac{2\pi \nu t}{\lambda }\,\sin \,\frac{2\pi x}{\lambda }\] \[\Rightarrow \,\,\,\lambda =6\,cm\] Therefore the separation between adjacent nodes \[\Rightarrow \,\,\,\frac{\lambda }{2}=3\,cm\]


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