A) \[\pi \]
B) \[\pi /2\]
C) \[\pi /4\]
D) \[\pi /6\]
Correct Answer: B
Solution :
\[\phi =BA\,\cos \,\theta \] where \[\theta \] is the angle between area and field \[e=\frac{-d\phi }{dt}\,\,=\,\,-BA\,\sin \,\theta \,.\,\frac{d\theta }{dt}\,\] \[=\,\,BA\,\left( \frac{d\theta }{dt} \right)\,\cos (90+\theta )\] Here phase difference \[=\text{ }90{}^\circ .\]You need to login to perform this action.
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