2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-66

  • question_answer
    In an LCR circuit\[\operatorname{R} =100 ohm\]. When capacitance C is removed, the current lags behind the voltage by \[\pi /3\]. When inductance L is removed, the current leads the voltage by \[\pi /3\]. The impedance of the circuit is

    A) 50 ohm            

    B) 100 ohm

    C) 200 ohm                       

    D) 400 ohm

    Correct Answer: B

    Solution :

    When C is removed circuit becomes RL circuit hence tan \[\frac{\pi }{3}\,\,=\,\,\frac{{{X}_{L}}}{R}\]                                 .... (i) When L is removed circuit becomes RC circuit hence tan \[\frac{\pi }{3}\,\,=\,\,\frac{{{X}_{C}}}{R}\]                                .... (ii) From equations (i) and (ii) we obtain\[{{X}_{L}}={{X}_{C}}\]. This is the condition of resonance and in resonance and in resonance \[Z=R=100\,\,\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner