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NEET Sample Paper NEET Sample Test Paper-66

  • question_answer
    If we use \[100\,\,\Omega \] and \[200\,\,\Omega \] resistance in place of R and S, we get null deflection at\[{{l}_{1}}=33.0\,cm\]. If we intercharge the resistance, the null deflection was found to be at\[{{l}_{2}}=67.0\,cm\]. The end correction \[\alpha \,\,and\,\,\beta \] should be

    A) \[\alpha  =1 cm,\,\,\beta = 1 cm\]

    B) \[\alpha  =2 cm,\,\,\beta = 1 cm\]

    C) \[\alpha  =1 cm,\,\,\beta = 2 cm\]

    D) none of these

    Correct Answer: A

    Solution :

    \[\alpha \,\,=\,\,\frac{{{R}_{2}}{{l}_{1}}-{{R}_{1}}{{l}_{2}}}{{{R}_{1}}-{{R}_{2}}}\] \[=\,\,\frac{(200)(33)-(100)(67)}{100-200}\,\,=\,\,\,1\,\,cm\] \[\beta \,\,=\,\frac{{{R}_{1}}{{l}_{1}}-{{R}_{2}}{{l}_{2}}}{{{R}_{1}}-{{R}_{2}}}-100\] \[=\,\,\frac{(100)-(200)(67)}{100-200}\,\,\,-\,\,100=1\,cm\]


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