NEET Sample Paper NEET Sample Test Paper-66

  • question_answer
    Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6 and surface tensions are 60 and 50 dyne/cm respectively Ratio of heights of liquids in the two tubes \[{{h}_{1}}/{{h}_{2}}\] is

    A) \[\frac{10}{9}\]                         

    B) \[\frac{3}{10}\]

    C) \[\frac{10}{3}\]                         

    D) \[\frac{9}{10}\]

    Correct Answer: D

    Solution :

    Ascent formula \[h=\frac{2T\cos \,\theta }{rdg}\] \[\Rightarrow \,\,\frac{{{h}_{1}}}{{{h}_{2}}}\,\,=\,\frac{{{T}_{1}}}{{{T}_{2}}}\,\,\times \,\,\frac{{{d}_{2}}}{{{d}_{1}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(r,\,\,\theta \,\,and\,\,g\,\,are\,\,constants)\]\[\Rightarrow \,\,\frac{{{h}_{1}}}{{{h}_{2}}}\,\,=\,\frac{60}{50}\,\,\times \,\,\frac{0.6}{0.8}=\frac{9}{10}\]


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