A) 4
B) 3
C) 2
D) 1
Correct Answer: A
Solution :
\[1{{s}^{2}}\,2{{s}^{2}}\,2{{p}^{6}}\,3{{s}^{2}}\,3{{p}^{6}}\,4{{s}^{2}}\] principal quantum no. is 4 so it belongs to 4th period.You need to login to perform this action.
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