A) \[d-electrons in Fe \left( Z = 26 \right)\]
B) \[p-electrons in Ne \left( Z = 10 \right)\]
C) \[s-electrons in Mg \left( Z = 12 \right)\]
D) \[p-electrons in Cl \left( Z=17 \right)\]
Correct Answer: D
Solution :
Number of d-electrons is \[{{\operatorname{Fe}}^{2+}}= 6\] Number of p-electrons in \[Cl= 11\].You need to login to perform this action.
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