A) \[\frac{V}{K+2}\]
B) \[2+\frac{K}{3V}\]
C) \[\frac{2V}{K+2}\]
D) \[\frac{3V}{K+2}\]
Correct Answer: D
Solution :
Initially, Equivalent capacitance of the system \[{{C}_{eq}}=3C\] Total charge \[Q =(3C)V\] Finally, Equivalent capacitance of the system \[{{C}_{eq}}\,\,=\,\,\,KC+2C\] Hence common potential \[\,V=\frac{Q}{(KC+2C)}=\frac{3CV}{(K+2)C}\,\,=\,\,\frac{3V}{K+2}\]You need to login to perform this action.
You will be redirected in
3 sec