NEET Sample Paper NEET Sample Test Paper-66

  • question_answer
    If the dimensions of a physical quantity are given by \[{{M}^{a}}{{L}^{b}}{{T}^{c}}\], then the physical quantity will be

    A) \[pressure\,\,if\,\,a=1,\,\,b=-1,\,\,c=-2\]

    B) \[velocity\,\,if\,\,a=1,\,\,b=0,\,\,c=-1\]

    C) \[acceleration\,\,if\,\,a=1,\,\,b=1,\,\,c=-2\]

    D) \[force\,\,if\,\,a=0,\,\,b=-1,\,\,c=-2\]

    Correct Answer: A

    Solution :

    (i) Dimensions of velocity \[=\,\,\left[ {{M}^{0}}{{L}^{1}}{{T}^{-1}} \right]\] Here, \[a\text{ }=0,\,\,b=1,\,\,c=-1\]. (ii) Dimensions of acceleration \[=\,\,\left[ {{M}^{0}}{{L}^{1}}{{T}^{-2}} \right]\] Here, \[a\text{ }=0,\,\,6=\text{ }1,\,\,c=-2\] (iii) Dimensions of force \[=\,\,\left[ {{M}^{1}}{{L}^{1}}{{T}^{-2}} \right]\] Here, \[\operatorname{a} =1, b=1,\,T=-2\] (iv) Dimensions of pressure \[=\,\,\left[ {{M}^{1}}{{L}^{-1}}{{T}^{-2}} \right]\] \[\therefore \,\,\,\,Here\,\,a=1,\,\,b=-1,\,\,c=-2\] \[\therefore \] The physical quantity is pressure.


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