A) 49
B) 69
C) 89
D) 98
Correct Answer: A
Solution :
\[BaC{{l}_{2}}\,\,\rightleftharpoons \,\,B{{a}^{2+}}\,+\,\,2C{{l}^{-}}\] \[\begin{matrix} Initially \\ After\,\,dissociation \\ \end{matrix}\,\,\,\,\,\,\,\,\begin{matrix} 1 \\ 1\alpha \\ \end{matrix}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\begin{matrix} 0 \\ \alpha \\ \end{matrix}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\begin{matrix} 0 \\ 2\alpha \\ \end{matrix}\] \[Total=1-\alpha +\alpha +2\alpha =1+2\alpha \] \[\alpha \,=\,\,\frac{1.98-1}{\alpha }\,\,=\,\,\frac{0.98}{\alpha }\,\,\,=\,\,0.49\,\] for a mole \[\alpha = 0.49\] For 0.01 mole \[\alpha \,\,=\, \frac{0.49}{0.01}\,\,=\,\,49\]
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