A) \[CO\,\,and\,\,C{{l}^{2}}\]
B) \[S{{O}_{2}}\,\,and\,\,C{{l}^{2}}\]
C) \[{{H}_{2}}S\,\,and\,\,B{{r}_{2}}\]
D) \[N{{H}_{3}}\,\,and\,\,S{{O}_{2}}\]
Correct Answer: B
Solution :
\[S{{O}_{2}}\] bleaches by reduction while chlorine bleaches colour of flowers by oxidation.
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