A) \[VO_{2}^{+}\,\to \,{{V}_{2}}{{O}_{3}}\]
B) \[Na\,\to \,N{{a}^{+}}\]
C) \[CrO_{4}^{2-}\,\to \,\,C{{r}_{2}}O_{7}^{2-}\]
D) \[Z{{n}^{2+}}\,\to \,\,Zn\]
Correct Answer: C
Solution :
\[\begin{matrix} CrO_{4}^{2-} \\ x+[(-2)\times 4]=-2 \\ x=8-2=+\,6 \\ \end{matrix}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\begin{matrix} C{{r}_{2}}O_{7}^{2-} \\ 2x+(-2)\times 7=-2 \\ 2x=14-2=12 \\ \end{matrix}\] \[x=\frac{12}{2}=+6\] In this reaction oxidation and reduction are not involved because there is no change in oxidation number,
You need to login to perform this action.
You will be redirected in
3 sec
