A) hydrogen is liberated at the anode
B) hydrogen is liberated at the cathode
C) no reaction takes place
D) hydride ion migrates towards cathode
Correct Answer: A
Solution :
\[{{M}^{+}}{{H}^{-}}\,\,\to \,\,\,{{M}^{+}}\,\,+\,\,\underset{Hydride\,\,ion}{\mathop{{{H}^{-}}}}\,\] \[{{H}^{-}}\,\to \,\,\frac{1}{2}{{H}_{2}}+{{e}^{-}}~(At\,\,anode)\]
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