A) \[1 : 1\]
B) \[1 : 2\]
C) \[2 : 1\]
D) \[4 : 1\]
Correct Answer: A
Solution :
\[\frac{{{d}_{1}}}{{{d}_{2}}}=\frac{1}{2},\,\,\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{2}{1}\,\,\,\,\because \,\,\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{V{{ & }_{2}}}{{{V}_{1}}}\times \frac{{{T}_{1}}}{{{T}_{2}}}\,\,=\,\frac{{{T}_{1}}.{{d}_{1}}}{{{T}_{2}}.{{d}_{2}}}\]\[\frac{{{P}_{1}}}{{{P}_{2}}}\,=\,\,\frac{2}{1}\,\,\cdot \,\,\frac{1}{2}=\frac{1}{1}\,\]
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