A) 0.9555 M and 1.910 M
B) 1.910 M and 0.955 M
C) 1.90 M and 1.090 M
D) 0.477 M and 0.477 M
Correct Answer: B
Solution :
\[{{M}_{N{{a}_{2}}C{{O}_{3}}}}\,=\,\,{{M}_{N{{a}^{+}}}}\times 2={{M}_{CO_{3}^{2-}}}\,and\,\,{{M}_{N{{a}_{2}}C{{O}_{3}}}}\]\[=\,\,\frac{25.3\times 1000}{106\times 250}\,=\,\,0.955\] \[\Rightarrow \,\,\,0.955\,\,\times \,\,2\,\,=\,\,1.91\text{ }M\] Thus is correct.You need to login to perform this action.
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