A) Copper chloride in water
B) \[NaCl\] in water
C) \[{{H}_{2}}S{{O}_{4}}\]
D) Water
Correct Answer: B
Solution :
Since discharge potential of water is greater than that of sodium so water is reduced at cathode instead of \[N{{a}^{+}}\]. \[Cathode:\,\,\,\,\,\,\,\,{{H}_{2}}O+{{e}^{-}}\,\to \,\,\frac{1}{2}\,{{H}_{2}}+O{{H}^{-}}\] \[Anode:\,\,\,\,\,\,\,\,C{{l}^{-}}\,\to \,\,\frac{1}{2}\,C{{l}_{2}}+{{e}^{-}}\]
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